Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Solve the system of equations using substitution.
y= 3/4x-7
4x- 6y=50

Sagot :

Y=3/4x-7
4x-6y=50

4x-6y=50
4x-6(3/4x-7)=50
4x-18/4x+42=50
-1/2x=8
x=-16

y=3/4(-16)-7
y=-12-7
y=-19
Lilith
[tex]\begin{cases} y= \frac{3 }{4}x-7 \\ 4x- 6y=50 \end{cases}\\ \\\begin{cases} y= \frac{3 }{4}x-7 \\ 4x- 6(\frac{3 }{4}x-7)=50 \end{cases}\\ \\\begin{cases} y= \frac{3 }{4}x-7 \\ 4x- \frac{9 }{2}x+42=50 \end{cases}\\ \\ \begin{cases} y= \frac{3 }{4}x-7 \\ 4x- 4\frac{1 }{2}x =50 -42\end{cases}[/tex]

[tex]\begin{cases} y= \frac{3 }{4}x-7 \\ - \frac{1 }{2}x =8 \ \ /*(-2)\end{cases}\\ \\ \begin{cases} y= \frac{3 }{4}*(-16)-7 \\ x =-16\end{cases}\\ \\ \begin{cases} y= -12-7 \\ x =-16\end{cases} \\ \\\begin{cases} y= -19 \\ x =-16\end{cases}[/tex]