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How can I solve y^2 + 13y + 12?

Sagot :

[tex](y + 1)(y + 12)[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] {y}^{2} + 13y + 12 \\ = {y}^{2} + 12y + 1y + 12 \\ taking \: common \: factor \: from \: the \: two \: pairs \\ = y(y + 12) + 1(y + 12) \\ = (y + 1)(y + 12)[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]

(y+1)(y+12) that’s what I got.
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