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Sagot :
Answer:
0.1357 = 13.57% of bolts will have a diameter greater than 1.211 inches
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 1.20 inches and a standard deviation of 0.01 inches.
This means that [tex]\mu = 1.20, \sigma = 0.01[/tex]
What proportion of bolts will have a diameter greater than 1.211 inches?
This is 1 subtracted by the p-value of Z when X = 1.211. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1.211 - 1.20}{0.01}[/tex]
[tex]Z = 1.1[/tex]
[tex]Z = 1.1[/tex] has a p-value of 0.8643.
1 - 0.8643 = 0.1357
0.1357 = 13.57% of bolts will have a diameter greater than 1.211 inches
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