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Sagot :

Answer:

∠ EDC = 55°

Step-by-step explanation:

Since Δ ADE is isosceles then the 2 base angles are congruent , then

∠ EDA = [tex]\frac{180-20}{2}[/tex] = [tex]\frac{160}{2}[/tex] = 80°

Similarly for Δ BCD

∠ CDB = [tex]\frac{180-90}{2}[/tex] = [tex]\frac{90}{2}[/tex] = 45°

The 3 angles on AB sum to 180° , that is

80° + ∠ EDC + 45° = 180°

∠ EDC + 125° = 180° ( subtract 125° from both sides )

∠ EDC = 55°

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