Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
0.1875 = 18.75% probability that a battery will last 15 hours or more given that it has lasted 10 hours or more.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Lasting 10 hours or more.
Event B: Lasting 15 hours or more.
The probability that a battery will last 10 hours or more is 80%.
This means that [tex]P(A) = 0.8[/tex]
Probability of lasting 10 hours or more and 15 hours or more.
This is the probability of lasting 15 hours or more(if it has lasted 15 or more, it has lasted 10 or more).
The probability that a battery will last 15 hours or more is only 15%, which means that [tex]P(A \cap B) = 0.15[/tex]
What is the probability that a battery will last 15 hours or more given that it has lasted 10 hours or more?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.8} = 0.1875[/tex]
0.1875 = 18.75% probability that a battery will last 15 hours or more given that it has lasted 10 hours or more.
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
