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Sagot :
Answer:
A. 0.028
B. 0.0628
C. 0.45
Step-by-step explanation:
A. Calculation to determine the probability that it is adefective hard drive and from plant II
Using CONDITIONAL PROBABILITY formula
P(B∩A2) =P(A2)P(B|A2)
Let plug in the formula
P(B∩A2)= 0.35×0.08
P(B∩A2)= 0.028
Therefore the probability that it is adefective hard drive and from plant II will be 0.028
B. Calculation to determine the probability that a randomly selected hard drive is defective
Using LAW OF TOTAL PROBABILITY formula
P(B) =P(A1)P(B|A1) +P(A2)P(B|A2) +P(A3)P(B|A3)
Let plug in the formula
P(B)= 0.54×0.04 + 0.35×0.08 + 0.11×0.12
P(B)=0.0216+0.028+0.0132
P(B)= 0.0628
Therefore the probability that a randomly selected hard drive is defective is 0.0628
C. Calculation to determine the probability that it came from plant II
Using CONDITIONAL PROBABILITY formula two twice
P(A2|B) =P(A2∩B)/P(B)
Let plug in the formula
P(A2|B)=0.0280/0.0628
P(A2|B)= 0.45
Therefore the probability that it came from plant II is 0.45
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