Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Find the equation of the parabola which has the given vertex V, which passes through the given point P, and which has the specified axis of symmetry. V(4,−2),P(2,14), vertical axis of symmetry.

Sagot :

MrRoyal

Answer:

[tex]y = 4(x - 4)^2 - 2[/tex]

or

[tex]y=4x^2 -32x + 62[/tex]

Step-by-step explanation:

Given

[tex]V = (4,-2)[/tex] --- vertex

[tex]P = (2,14)[/tex] --- point

Required

The equation of the parabola

The equation of the parabola is of the form

[tex]y = a(x - h)^2 + k[/tex]

Where

[tex]V (4,-2) = (h,k)[/tex] ---- the vertex

So, we have:

[tex]y = a(x - h)^2 + k[/tex]

[tex]y = a(x - 4)^2 - 2[/tex]

In [tex]P = (2,14)[/tex], we have:

[tex](x,y) = (2,14)[/tex]

Substitute [tex](x,y) = (2,14)[/tex] in [tex]y = a(x - 4)^2 - 2[/tex]

[tex]14 = a(2 - 4)^2 - 2[/tex]

[tex]14 = a(- 2)^2 - 2[/tex]

[tex]14 = a*4 - 2[/tex]

[tex]14 = 4a - 2[/tex]

Collect like terms

[tex]4a = 14 +2[/tex]

[tex]4a = 16[/tex]

Divide both sides by 4

[tex]a= 4[/tex]

So:

[tex]y = a(x - 4)^2 - 2[/tex] becomes

[tex]y = 4(x - 4)^2 - 2[/tex]

Open bracket to express the equation in standard form

[tex]y=4(x^2 -8x + 16) - 2[/tex]

[tex]y=4x^2 -32x + 64 - 2[/tex]

[tex]y=4x^2 -32x + 62[/tex]

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.