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calculate the interest paid when 4920 is invested at 13% p.a simple interest for eight years​

Sagot :

Answer:

I'll setup the problem and you can do the calculations

Step-by-step explanation:

The formula for simple interest:

I = P*r*t

I = interest

P = principle or amount invested

r = interest rate per period (period is a year)

t = number of periods

P = 4920

r = .13

t = 8

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Required solution :

Here we have been provided with the principal , rate of interest and time period for which the sum of rupees is invested.

  • Principal (P) = Rs.4920
  • Rate (r) = 13%
  • Time (T) = 8 years

Now here we know that simple Interest is calculated by the formula,

  • [tex]\bf{\boxed{\bf{S.I.\: = \: \dfrac{P \times R \times T}{100}}}} \: \red\bigstar[/tex]

Here in this formula,

  • P is Principal
  • R is rate of interest
  • T is time

Putting there values in the formula,

[tex]\longrightarrow \: \sf{S.I. \: = \: \dfrac{4920 \times 13 \times 8}{100} }[/tex]

[tex]\longrightarrow \: \sf{S.I. \: = \: \dfrac{492 \times 13 \times 8}{10} }[/tex]

[tex]\longrightarrow \: \sf{S.I. \: = \: \dfrac{492 \times 13 \times \cancel{8}}{ \cancel{10}} }[/tex]

[tex]\longrightarrow \: \sf{S.I. \: = \: \dfrac{492 \times 13 \times 4}{ 5} }[/tex]

[tex]\longrightarrow \: \sf{S.I. \: = \: \dfrac{492 \times 52}{ 5} }[/tex]

[tex]\longrightarrow \: \sf{S.I. \: = \: \dfrac{25584}{ 5} }[/tex]

[tex] \longrightarrow \: \sf{S.I. \: = \: \cancel\dfrac{25584}{ 5} }[/tex]

[tex] \longrightarrow \: \orange{\boxed{\bf{S.I. \: = \: 5116.8}}}[/tex]

[tex]\underline{\bf{Henceforth, \: interest \: paid \: is \: of \: Rs.5116.8}}[/tex]