maeiklah2004
Answered

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Consider a normal distribution of values with a mean of 32 and a standard
deviation of 1.5. Find the probability that a value is less than 36.8.


Anyone know?

Sagot :

JeanaShupp

Answer: The probability that a value is less than 36.8 is 0.9993.

Step-by-step explanation:

Let X be the random variable that normally distributed.

Given: [tex]\mu=32,\sigma=1.5[/tex]

The probability that a value is less than 36.8 = [tex]P(X<36.8)[/tex]

[tex]=P(\frac{X-\mu}{\sigma}<\frac{36.8-32}{1.5})\\\\=P(Z<3.2)\ \ \ [Z=\frac{X-\mu}{\sigma}]\\\\=0.9993[/tex][Using P-value calculator]

Therefore, The probability that a value is less than 36.8 is 0.9993.

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