Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:
The population in 11 years will be of 53,199.
Step-by-step explanation:
Equation for a population that doubles every n years.
The population of an specie, after t years, considering that is doubles after n years, is given by an equation in the following format:
[tex]P(t) = P(0)(2)^{\frac{t}{n}}[/tex]
In which P(0) is the initial population.
The population doubles every 15 years, and the current population is 32,000
This means that [tex]n = 15, P(0) = 32000[/tex]. So
[tex]P(t) = P(0)(2)^{\frac{t}{n}}[/tex]
[tex]P(t) = 32000(2)^{\frac{t}{15}}[/tex]
What will be the population in 11 years?
This is P(11). So
[tex]P(t) = 32000(2)^{\frac{t}{15}}[/tex]
[tex]P(11) = 32000(2)^{\frac{11}{15}}[/tex]
[tex]P(11) = 53199[/tex]
The population in 11 years will be of 53,199.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.