Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Answer:
The genotypes of the original parents are
- Male: X⁺Y
- Female: X⁻X⁻
The Chi-square analysis leads us to accept the prediction of the parental genotypes.
Explanation:
Due to technical problems, you will find the complete explanation in the attached files.
(a) The genotypes for the original parents (P generation) are
Male: X⁺Y
Female: X⁻X⁻
(b) The prediction of the parental genotype is accepted by the Chi-squared test analysis.
What is the eye color pattern in fruit flies?
Drosophila Melanogaster is a fruit fly with abnormally big, brightly colored eyes.
The range in color from red to sepia to white reveals a lot about the genetic makeup of the fly.
(a) E = + ⇒ Dominant allele coding for wild-type eyes
e = - ⇒ Recessive allele coding for white eyes
Now, Crossing the : male wild-type with a female white-eyed
(Parental) = X⁺Y x X⁻X⁻
(Phenotype) = wild white
(Gametes) = X⁺ Y X⁻ X⁻
(Punnett square) = X⁺ Y
X⁻ = X⁺X⁻ X⁻Y
X⁻ = X⁺X⁻ X⁻Y
In (F1)generation = 2/4 = 1/2 = 50% of the progeny are expected to be wild-type females.
And 2/4 = 1/2 = 50% of the progeny are expected to be white-eyed males.
Thus, the percentages are almost 50:50, as the expected ones.
So, the genotypes of the original parents are
Male: X⁺Y
Female: X⁻X⁻
(b) Using Chi-squared test :
Observed fruit fly type:
Wild Type Male - 25
Wild Type Female - 31
White-eyed Male - 22
White-eyed Female - 24
Expected fruit fly type:
Wild Type Male - 25
Wild Type Female - 25
White-eyed Male - 25
White-eyed Female - 25
Now, chi square [tex]= \sum\dfrac{(O- E)^2 }{E}[/tex]
By putting numbers in the formula, we are getting
Wild Type Male - 0.16
Wild Type Female - 1.44
White-eyed Male - 0.36
White-eyed Female - 0.04
Now, X² = 0.16 + 1.44 + 0.36 + 0.04 = 2
Critical value = 7.82
X² (2) < critical value (7.82)
Thus, this is the evidence to accept the given hypothesis.
Learn more about fruit flies here:
https://brainly.com/question/7274152
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.