Answered

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Find the quotient of these complex numbers (6-I) divided by (4+3i)=

Sagot :

aklee18oo

Answer:

[tex]\frac{21}{25} -\frac{22}{25} i[/tex]

Step-by-step explanation:

We can start by writing the division as a fraction:

[tex]\frac{6-i}{4+3i}[/tex]

In order to rationalize the denominator, we need to multiply by the conjugate:

[tex]\frac{6-i}{4+3i} *\frac{4-3i}{4-3i}\\\\\frac{(6-i)(4-3i)}{4^2-(3i)^2}\\\\\frac{24-18i-4i+3i^2}{16+9}\\\\\frac{24-22i-3}{25}\\\\\frac{21-22i}{25} \\\\\frac{21}{25} -\frac{22}{25} i[/tex]

Answer:

21/25-22/25 i

Step-by-step explanation:

A p e x

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