Answered

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In a family with 6 ​children, excluding multiple​ births, what is the probability of having 6 ​girls? Assume that a girl is as likely as a boy at each birth

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Answer:

There's is a 25% chance on having all 6 births be girls. There is a 50-50 chance of a boy nor a girl. However, it is possible.

The probability of having 6 ​girls will be 1/64.

What is probability?

Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.

In a family with 6 ​children, excluding multiple​ births.

Then the probability of having 6 ​girls will be

Leaving out the third gender, let's suppose that there is an equal chance of having a girl or a boy.

Any child can be either a boy or a girl, with each having equal probability of = 1/2

Each of these blank spaces can be filled in 2 ways : B and G (denoting 'B' and 'G' respectively)

Probability of first blank being a ''G' is = 1/2

and second blanks too being a “G” is = 1/2

Thus, probability of each blank individually being a “G” = 1/2

Thus, probability of all being a “G” = (1/2) (1/2)  (1/2) (1/2) (1/2)* (1/2) = (1/2)6 = 1/64

Thus, probability of 6 children being all 6 girls = 1/64

More about the probability link is given below.

https://brainly.com/question/795909

#SPJ2

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