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A 6-hp pump is used to raise water to an elevation of 12 meters. If the mechanical efficiency of the pump is 85 percent, determine the maximum volume flow rate of water in gallons per hour.

Sagot :

batolisis

Answer:

29481.60 gallons/hour

Explanation:

Pump ( in )  = 6 - hp

Elevation ( h )  = 12 meters

mechanical efficiency of pump ( η pump )  = 85% = 0.85

Calculate for  the maximum volume flow rate of water

1 - hp = 745.7 w

η pump = mgh / W * in

mgh = η pump * W * in

i.e. pVgh  = η pump * W * in

∴ V = η pump * W * in / pgh

      = 0.82 * ( 745.7 * 6 ) / 1000 * 9.81 * 12

      = 3668.844 / 117720

      = 0.031 m^3 /s  =  29481.601 gallons/hour

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