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You are driving West at 38 m s . Ahead of you is an ambulance traveling East (towards you) at 31 m s . You hear the ambulance siren at a frequency of 411 Hz. What is the actual frequency that the ambulance is emitting

Sagot :

Answer:

The right answer is "335.18 Hz".

Explanation:

Given:

Velocity of observer,

[tex]v_0=38 \ m/s[/tex]

Velocity of source,

[tex]v_s=31 \ m/s[/tex]

Frequency,

[tex]f=411 \ Hz[/tex]

As we know,

⇒  [tex]F=(\frac{v-v_0}{v+v_s} )\times f[/tex]

        [tex]=(\frac{343-38}{343+31} )\times 411[/tex]

        [tex]=(\frac{305}{374} )\times 411[/tex]

        [tex]=0.815\times 411[/tex]

        [tex]=335.18 \ Hz[/tex]