Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Answer:
Explanation:
moles of hydrochloric acid = 50 x 10⁻³ x .75 = 37.5 x 10⁻³ moles in HCl solutions.
moles of NaOH in its solution = 10 x 10⁻³ x 1 moles = 10 x 10⁻³ moles .
10 x 10⁻³ moles of NaOH will neutralise 10 x 10⁻³ moles of HCl .
HCl remaining = (37.5 - 10 ) x 10⁻³ moles = 27.5 x 10⁻³ moles
volume of solution = 50 + 10 = 60 mL = 60 x 10⁻³ L
molarity of remaining HCl = 27.5 x 10⁻³ / 60 x 10⁻³
= .4583 M .HCl
concentration of H⁺ = .4583 M
pH = - log ( .4583 )
= .34 .
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.