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Sagot :
September 22, 2014 at 5:10AM.
33 degrees C= 91.4 degrees F.
Assuming that she had a normal 98.6 temperature .Based on the info given 1.5 degrees of temperature lost per hour.
1.5 x 4 hours = 6 degrees lost. An additional 50 min would be 7.2 degrees lost.
10:00AM - 4 hours 50 min = 5:10AM
33 degrees C= 91.4 degrees F.
Assuming that she had a normal 98.6 temperature .Based on the info given 1.5 degrees of temperature lost per hour.
1.5 x 4 hours = 6 degrees lost. An additional 50 min would be 7.2 degrees lost.
10:00AM - 4 hours 50 min = 5:10AM
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