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How many grams of gas must be released from a 32.0 L sample of CO2(g) at STP to reduce the volume to 16.6 L at STP?

Sagot :

maacastrobr

Answer:

30.3 g

Explanation:

At STP, 1 mol of any gas will occupy 22.4 L.

With the information above in mind, we calculate how many moles are there in 32.0 L:

  • 32.0 L ÷ 22.4 L/mol = 1.43 mol

Then we calculate how many moles would there be in 16.6 L:

  • 16.6 L ÷ 22.4 L/mol = 0.741 mol

The difference in moles is:

  • 1.43 mol - 0.741 mol = 0.689 mol

Finally we convert 0.689 moles of CO₂ into grams, using its molar mass:

  • 0.689 mol * 44 g/mol = 30.3 g
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