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Write the equation of the circle centered at ( – 3, (-3, – 10) with radius 2.​

Sagot :

ferrybukantoro

Step-by-step explanation:

the equation of the circle centered at (-3, – 10)

=> (x+3)²+(y+10)²=2²

<=> x²+6x+9+y²+20y+100=4

x²+y²+6x+20y+105=0

Let's see

[tex]\\ \rm\dashrightarrow (x-h)^2+(y-k)^2=r^2[/tex]

  • (h,k)=(-3,-10)

[tex]\\ \rm\dashrightarrow (x+3)^2+(y+10)^2=2^2[/tex]

[tex]\\ \rm\dashrightarrow (x+3)^2+(y+10)^2=4[/tex]

[tex]\\ \rm\dashrightarrow x^2+y^2+6x+20y+105=0[/tex]

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