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Sagot :
The value of the solubility of product for CaSO₄ in pure water at 0 °C is 1.1881
What is solubility of product?
The solubility of product (Ksp) is defined as the concentration of products raised to their coefficient coefficients. This is illustrated below:
mA <=> nC + eD
Ksp = [C]^n × [D]^e
With the above information in mind, we can obtain the solubility of the product. This is illustrated below:
Dissociation equation
CaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)
From the balanced equation above,
1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻
How to determine the concentration of Ca²⁺ and SO₄²⁻
From the balanced equation above,
1 mole of CaSO₄ contains 1 mole of Ca²⁺ and 1 mole of SO₄²⁻
Therefore,
1.09 g/L of CaSO₄ will also contain
- 1.09 g/L of Ca²⁺
- 1.09 g/L of SO₄²⁻
How to determine the solubility of product
- Concentration of Ca²⁺ = 1.09 g/L
- Concentration of SO₄²⁻ = 1.09 g/L
- Solubility of product (Ksp) =?
CaSO₄(aq) → Ca²⁺(aq) + SO₄²⁻(aq)
Ksp = [Ca²⁺] × [SO₄²⁻]
Ksp = 1.09 × 1.09
Ksp = 1.1881
Learn more about solubility of product:
https://brainly.com/question/4530083
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