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0=x^(2)+2x-3 Solve using Quadratic Formula

Sagot :

Answer:

Step-by-step explanation:

x^2 + 2x - 3 =0

x^2 + 3x - x -3 = 0

(x) x (x+3) - (x + 3) = 0

(x+3) x (x-1) = 0

x+3=0

x-1=0

x=-3

x=3

x1 =-3, x2 = 1

Corsaquix

Answer:

[tex]x=1,\\x=-3[/tex]

Step-by-step explanation:

The quadratic formula is given by [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex], where [tex]x[/tex] represents both real and nonreal solutions to a quadratic in standard form [tex]ax^2+bx+c[/tex].

Thus, with the given quadratic [tex]x^2+2x-3[/tex], we can assign values:

  • [tex]a=1[/tex]
  • [tex]b=2[/tex]
  • [tex]c=-3[/tex]

Substituting in these values to the quadratic formula, we have:

[tex]x=\frac{-2\pm\sqrt{2^2-4(1)(-3)}}{2(1)}, \\\\x=\frac{-2\pm\sqrt{16}}{2},\\\\x=\frac{-2\pm 4}{2},\\\\\begin{cases}x=\frac{-2+4}{2},x=\frac{2}{2}=\boxed{1}\\x=\frac{-2-4}{2},x=\frac{-6}{2}=\boxed{-3}\end{cases}[/tex]

Verify by factoring:

[tex]x^2+2x-3=0,\\(x+3)(x-1)=0,\\\begin{cases}x+3=0,x=\boxed{-3}\:\checkmark\\x-1=0,x=\boxed{1}\:\checkmark\end{cases}[/tex]

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