Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer: Electrostatic potential energy of the given system is
U=1/4π∈*(96/5)*Q²/a
Explanation:
consider spherical shell of inner radius a (taken as x) and outer radius 2a ,carrying charge Q and volume charge density ρ=Q/4π(2a)³...........................(1)
then voume of the shell=4πx²dx
charge on the shell inner part of the shell.q1=4πx²dx ρ
charge on this ,in case of sphereical type,q2=4/3*πx³ ρ
then electrostatic energy of sperical charge of radius a (which we taken as x) and sperical shell of radius x and thickness dx is,
dU=1/4π∈ *(q1q2)/x
by placing value of q1 and q2 from above , we will get a equation
dU=1/4π∈*(16/3*π²ρ²x [tex]x^{4}[/tex]dx
then total electrostatic energy of sperical charge by integrating from limit a to 2a and putting value of ρ then we will get
U=1/4π∈*(96/5)Q²/a
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.