Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

PLEASE HELP. requires 35 mL of NaOH(aq) to neutralize
10. mL of 0.10 M HCl(aq). The concentration of the NaOH(aq) is

Sagot :

samueladesida43

Answer:

0.0286M

Explanation:

Using the formula as follows:

CaVa = CbVb

Where;

Ca = concentration of HCl acid (M)

Cb = concentration of NaOH base (M)

Va = volume of HCl acid (mL)

Vb = volume of NaOH base (mL)

According to the information provided in this question;

Ca = 0.10 M

Cb = ?

Va = 10mL

Vb = 35mL

Using CaVa = CbVb

Cb = CaVa/Vb

Cb = (0.10 × 10) ÷ 35

Cb = 1 ÷ 35

Cb = 0.0286M

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.