Answer:
33.4 °C
Explanation:
The final temperature of water will be the equilibrium temperature. This can be obtained as follow:
Mass of copper (M꜀) = 300 g
Initial temperature of copper (T꜀) = 285 °C
Specific heat capacity of copper (C꜀) = 0.385 J/gºC
Mass of water (Mᵥᵥ) = 1000 g
Initial temperature of water (Tᵥᵥ) = 26.5 °C
Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC
Equilibrium temperature (Tₑ) =?
Heat lost by copper = Heat gained by water
M꜀C꜀(T꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
300 × 0.385 (285 – Tₑ) = 1000 × 4.184 (Tₑ – 26.5)
115.5(285 – Tₑ) = 4184(Tₑ – 26.5)
Clear the bracket
32917.5 – 115.5Tₑ = 4184Tₑ – 110876
Collect like terms
32917.5 + 110876 = 4184Tₑ + 115.5Tₑ
143793.5 = 4299.5Tₑ
Divide both side by 4299.5
Tₑ = 143793.5 / 4299.5
Tₑ = 33.4 °C
Therefore, the final temperature of water is 33.4 °C.
