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A gas occupies 11.2 L at 0.860 atm. What is the pressure if the volume becomes 0.00150 L?

Sagot :

samueladesida43

Answer:

6421.33 atm

Explanation:

Using Boyle's law equation as follows:

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

According to the provided information in this question;

P1 = 0.860 atm

P2 = ?

V1 = 11.2L

V2 = 0.00150 L

Using P1V1 = P2V2

P2 = P1V1/V2

P2 = 0.860 × 11.2/0.00150

P2 = 9.632 ÷ 0.00150

P2 = 6421.33 atm

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