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A straight has slope equals to 12 and y-intercept equals to -5. What's the equation for this straight line?


Sagot :

Answer:

[tex] \large{ \tt{❃ \: EXPLANATION}} : [/tex]

  • We're provided : Slope of straight line ( m ) = 12 & y - intercept ( c ) = - 5 and We're asked to find out the equation for this straight line.

  • You'll have to know : Equation of straight line in slope intercept form : y = mx + c where m is the slope & c is the y-intercept.

[tex] \large{ \tt{❁ \: LET'S \: START}} : [/tex]

  • Using Slope - intercept form of equation of straight line :

[tex] \boxed{ \large{ \tt{❈ \: y = mx + c}}}[/tex]

- Plug the values :

[tex] \large{ \tt{↬y = 12x + ( - 5)}}[/tex]

[tex] \large{ \tt{↬ \: y = 12x - 5}}[/tex]

[tex] ↬\large{\tt{12x - 5 = y}}[/tex]

[tex]↬ \large{ \boxed{ \bold{ \tt{12x - y - 5 = 0}}}}[/tex]

  • Hence , 12x - y - 5 = 0 is the required equation.

[tex] \tt{✺ \: STUDY \: MORE \: PROCASTINATE \: LESS !\:♪ }[/tex]

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