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The points (-6, r)
and
(6,3) lie on a line with slope 3/4. Find the missing coordinate r.

Sagot :

Answer:

r = -6

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

[tex]y = mx + b[/tex]

In which m is the slope and b is the y-intercept.

Slope 3/4

This means that [tex]m = \frac{3}{4}[/tex], and thus:

[tex]y = \frac{3}{4}x + b[/tex]

(6,3)

This means that when [tex]x = 6, y = 3[/tex]. We use this to find b. So

[tex]y = \frac{3}{4}x + b[/tex]

[tex]3 = \frac{3}{4}(6) + b[/tex]

[tex]b = 3 - \frac{18}{4} = \frac{12}{4} - \frac{18}{4} = -\frac{6}{4}[/tex]

So

[tex]y = \frac{3}{4}x - \frac{6}{4} = \frac{3x - 6}{4}[/tex]

(-6, r)

r is y when [tex]x = -6[/tex]. So

[tex]y = \frac{3(-6) - 6}{4} = -6[/tex]

So r = -6.