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Sagot :

Answer:

[tex] \sin( \alpha ) = \frac{4}{5} [/tex]

Step-by-step explanation:

as if we form an imaginary triangle with this line as hypotenuse

we get

  • base = 3 units
  • perpendicular = 4 units

using Pythagoras theorem:-

hyponteuse ² = perpendicular ² + base²

hyp² = 4² + 3²

hyp² = 16 + 9

[tex]hyp = \sqrt{25} [/tex]

hyp = 5 units

[tex] \sin( \theta ) = \frac{perpendicular}{hypotenuse} \\ \sin( \theta) = \frac{4}{5} [/tex]

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