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How many grams are in 3.7 moles of Na2O?

Sagot :

favourayoleyi

Answer:

mass = moles x molar mass

m= 3.7 x (23x2+16)

m= 3.7x62

m= 229.4g

198.4 grams are there is 3.7 moles of Na₂O.

The number of moles is defined as the ratio between given mass and molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\[/tex]

Given:

Number of moles= 3.7 moles

To find:

Mass=?

Molar mass of Na₂O= 62 g/mol

Thus substituting the values in the given formula

[tex]\text{Given mass}=\text{Number of moles}*\text{Molar mass}\\\\\text{Given mass}= 3.2 \text{moles}*62 \text{g/mol}\\\\\text{Given mass}=198.4 \text{g}[/tex]

Thus, 198.4 grams are there is 3.7 moles of Na₂O.

Learn more:

brainly.com/question/21911991

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