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What is the equation of the circle center (0, 3) and radius 4?

Sagot :

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Answer:

( x )² + ( y - 3 )² = 16

Step-by-step explanation:

The general format for circular equations is ( x - a )² + ( y - b )² = r²

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The equation of the circle is represented as :

[tex]\hookrightarrow (x - h) {}^{2} + (y - k) {}^{2} = (r) {}^{2} [/tex]

where, h is x-coordinate and k is y-coordinate of center of the circle, and "r" is radius of the given circle.

Therefore, the equation of the above circle will look like :

[tex]\hookrightarrow(x - 0) {}^{2} + (y - 3) {}^{2} = {4}^{2} [/tex]

[tex]\hookrightarrow {x}^{2} + (y - 3) {}^{2} = 16[/tex]

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[tex]\mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]

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