wassayhassan07
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The speed of an electron in an orbit around hydrogen atom is 2.2*10^6 ms^-1.It takes 1.5*10^-16 s for the electron to complete one orbit. Calculate the radius of the orbit. please help me ASAP!!

Sagot :

asuwafohjames

Answer:

5.3×10⁻¹¹ m

Step-by-step explanation:

Applying,

v = 2πr/t................ Equation 1

Where v = speed of the electron in the orbit, r = radius of the orbit, t = time, π = pie

make r the subject of the equation

r = vt/2π................ Equation 2

From the question,

Given: v = 2.2×10⁶ m/s, t = 1.5×10⁻¹⁶ s

Constant: π = 3.14

Susbtitute these values into equation 2

r = (2.2×10⁶×1.5×10⁻¹⁶)/(3.14×2)

r = (3.3×10⁻¹⁰)/6.28

r = 5.3×10⁻¹¹ m

Hence the radius of the orbit is 5.3×10⁻¹¹ m

whitneytr12

Answer:

The radius of the orbit is: [tex]R=0.525 \AA[/tex]

Step-by-step explanation:

The period of a circular motion is the time to complete one orbit, then:

[tex]T=1.5*10^{-16}s[/tex]

Now, let's recall the tangential speed can be written as:

[tex]v=\frac{2\pi R}{T}[/tex]

R is the radius of the motion.

Let's solve the above equation for R.

[tex]R=\frac{vT}{2 \pi}[/tex]

[tex]R=\frac{2.2*10^{6}1.5*10^{-16}}{2 \pi}[/tex]

[tex]R=\frac{2.2*10^{6}1.5*10^{-16}}{2 \pi}[/tex]

[tex]R=5.25*10^{-11} \: m[/tex]

Therefore, the radius of the orbit is: [tex]R=0.525 \AA[/tex]

I hope it helps you!

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