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Can someone explain why we need to add the sides - 300+300+55+55+315+315 to get the answer 1340 for finding the perimeter for the diagram?

Can Someone Explain Why We Need To Add The Sides 3003005555315315 To Get The Answer 1340 For Finding The Perimeter For The Diagram class=

Sagot :

Hakuna111

Answer:

Step-by-step explanation:

Solution :-

we know that,

Area of a ∆ with sides a, b , c and semi- perimeter s is √[s * (s - a) * (s - b) * (s - c)] .

semi - perimeter = (a + b + c)/2 .

given sides of triangular field are 55m, 300m and 300m..

So,

→ s = (55 + 300 + 300) / 2 = 327.5m.

Than,

→ Area of triangular field = √[327.5 * (327.5 - 55) * (327.5 - 300) * (327.5 - 300)] = √[327.5 * 272.5 * 27.5 * 27.5] = 27.5√(327.5 * 272.5) = 27.5 * 298 = 8195 m².

Now given that,

→ Area of triangular field = (7/15)th area of circular park.

So,

→ 8195 = (7/15) * Area of circular park.

→ (8195 * 15)/7 = Area of circular park.

→ Area of circular park = 17560.7 m².

Therefore,

→ πr² = 17560.7

→ (22/7) * r² = 17560.7

→ r² = (17560.7 * 7) / 22

→ r = 74.74 m.

Hence,

→ Perimeter of the circular Park = 2πr = 2 * (22/7) * 74.74 = (3288.56)/7 = 469.8m. (Ans.)

Hope this answer helps you :)

Have a great day

Mark brainliest

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