jacksonworthington05
Answered

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Assume that y varies inversely with the
square of x, then solve.
When x is 5, y is 4/5. Find y when x is 8.

Sagot :

sreedevi102

Answer:

y = 5/16

Step-by-step explanation:

[tex]y\ \alpha\ \frac{1}{x^2}\\\\y = k \times \frac{1}{x^2}\\\\y = \frac{4}{5}, x = 5.\\\\\frac{4}{5} = k \times \frac{1}{5^2}\\\\\frac{4}{5} \times 5^2 = k\\\\20 = k\\\\Now \ find\ y, \ when \ x = 8\\\\y = k \times \frac{1}{x^2} = 20 \times \frac{1}{8^2} = 20 \times \frac{1}{64} = \frac{5}{16}[/tex]

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