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Find the sum of the first 41 terms of the following series, to the nearest integer. 4, 12,20,...

Sagot :

agentsecret991

Answer:

The sum of the first 41 terms is 6232

Step-by-step explanation:

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sreedevi102

Answer:

Sum of the first 41 terms = 6724

Step-by-step explanation:

[tex]a_{41} = a_1 + (n - 1 )d = 4 + (41 - 1) \times 8= 4 + 40 \times 8 = 324\\\\S_n = \frac{n}{2}(a_1 + a_n)\\\\s_{41} = \frac{41}{2} (4 + 324) = \frac{41}{2} \times 328 = 41 \times 164 = 6724[/tex]

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