Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Given an arithmetic sequence where a1=5 and a9=-19 find a42


Please help I’m so desperate I’ll give branliest

Sagot :

77saseabrooks

Answer:

-76/8 = -19/2

In an arithmetic sequence, the nth term, an, is given by the formula:

an = a1 + (n - 1)d, where a1 is the first term and d is the common difference.  

So, a9 = a1 + 8d

Substituting in the given data, 12 = 88 + 8d

                                                    -76 = 8d

                                                      d = -76/8 = -19/2

Step-by-step explanation:

i hoped this helped!

a1=a=5
a9=a+8d=-19
Since a=5
5+8d=-19
8d=-19-5
8d=-24
d=-24/8
d=-3
a42=a+41d
a42= 5+(41*5)
a42=5+205
a42=210

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.