Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:
The value of the test statistic is z = -0.877.
Step-by-step explanation:
Testing the difference in mean time spent on housework between husbands and wives.
At the null hypothesis, we test if there is no difference, that is, the subtraction of the means is 0:
[tex]H_0: \mu_H - \mu_W = 0[/tex]
At the alternate hypothesis, we test if there is a difference, that is, the subtraction of the means is different from 0.
[tex]H_1: \mu_H - \mu_W \neq 0[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{s}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.
0 is tested at the null hypothesis:
This means that [tex]\mu = 0[/tex]
For the wives the mean was 7 hours/week and for the husbands the mean was 4.5 hours/week. The standard deviation of the differences in time spent on house work was 2.85.
This means that [tex]X = 4.5 - 7 = -2.5, s = 2.85[/tex]
What is the value of the test statistic for testing the difference in mean time spent on housework between husbands and wives?
[tex]z = \frac{X - \mu}{s}[/tex]
[tex]z = \frac{-2.5 - 0}{2.85}[/tex]
[tex]z = -0.877[/tex]
The value of the test statistic is z = -0.877.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
