Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

What mass of water can be heated from 45°C to 70°C by the addition of 875 Joules?
Please I need this


Sagot :

Answer:

17000 joules.

Explanation:

Explanation:

With knowledge of the specific heat capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:

ΔH=mCΔT, where

ΔH=change in enthalpy (J)

m= mass of substance being heated (g) i.e. water in this question

C= specific heat capacity (J/g°C)

ΔT= change in temperature (°C)

We know mass=65g and ΔT=76°C−12°C=64°C

The specific heat capacity of water is 4.18J/g°C

Therefore, ΔH=65g⋅4.18Jg°C⋅64°C

=17388.8J

=17000J (2 significant figures)

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.