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What mass of water can be heated from 45°C to 70°C by the addition of 875 Joules?
Please I need this

Sagot :

ayeshafaisal14

Answer:

17000 joules.

Explanation:

Explanation:

With knowledge of the specific heat capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:

ΔH=mCΔT, where

ΔH=change in enthalpy (J)

m= mass of substance being heated (g) i.e. water in this question

C= specific heat capacity (J/g°C)

ΔT= change in temperature (°C)

We know mass=65g and ΔT=76°C−12°C=64°C

The specific heat capacity of water is 4.18J/g°C

Therefore, ΔH=65g⋅4.18Jg°C⋅64°C

=17388.8J

=17000J (2 significant figures)

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