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Line JK passes through J(2,7) and K(5, 11).
What is the slope of line JK?



Helppp


Sagot :

Answer: Slope is 4/3

Step-by-step explanation:  slope is change of y / change of x

k = Δy/Δx = (7-11) /(2-5) = -4 / -3 =  4/3

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