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What is the pressure exerted by 68.0 g of nitrogen trihydride gas in a 50.0L container at 30.0 C?

Sagot :

Answer:

Molecular mass of NH3 = ( 14 + 3 ) = 17 g

[tex]PV = \frac{m}{m _{r}} RT \\ P \times 50.0 \times {10}^{ - 6} = \frac{68.0}{17} \times 8.314 \times (30.0 + 273) \\ P = \frac{68.0 \times 8.314 \times 303}{17 \times 50.0 \times {10}^{ - 6} } \\ P = 2.02 \times {10}^{8} \: Pascals[/tex]

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