Answered

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A typical jar that has been tightened to a reasonable degree requires 2.0 N⋅m to open. If you grab a 8.2-cm-diameter jar lid with one hand so that your thumb and fingers exert equal magnitude forces on opposite sides of the lid, what is the magnitude of each of the forces?

Sagot :

Answer: 24.39 N

Explanation:

Given

Torque required to open the lid is [tex]\tau =2\ N.m[/tex]

diameter of lid [tex]d=8.2\ cm[/tex]

Force exerted by fingers and thumb forms a couple. So, torque can be written as

[tex]\Rightarrow \tau= F\times 2r\\\Rightarrow 2=F\times 8.2\times 10^{-2}\\\\\Rightarrow F=\dfrac{200}{8.2}\\\\\Rightarrow F=24.39\ N[/tex]

Thus, the magnitue of each force is 24.39 N

Answer: T = F x 2pir

2 = F x 8.2 x 10^-2

solve for F:

F = 24.39 N

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