Answered

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The half price of helium-5 is 7.6 X 10 to the power of negative 22 seconds and the half-life helium -9 is 7 x 10 to the power of negative 21-second approximately how many times greater is the half life of helium and -9 then that of helium -5

Sagot :

MrRoyal

Answer:

Approximately 9.211 times

Step-by-step explanation:

Given

[tex]x = 7.6 * 10^{-22}s[/tex] --- half life of helium-5

[tex]y = 7 * 10^{-21}s[/tex] --- half life of helium-9

Required

How many times greater is y than x

To do this, we simply divide y by x

[tex]\frac{y}{x} = \frac{7 * 10^{-21}s}{7.6 * 10^{-22}s}[/tex]

[tex]\frac{y}{x} = \frac{7 * 10^{-21}}{7.6 * 10^{-22}}[/tex]

Apply law of indices

[tex]\frac{y}{x} = \frac{7 * 10^{-21--22}}{7.6}[/tex]

[tex]\frac{y}{x} = \frac{7 * 10^{-21+22}}{7.6}[/tex]

[tex]\frac{y}{x} = \frac{7 * 10}{7.6}[/tex]

[tex]\frac{y}{x} = \frac{70}{7.6}[/tex]

[tex]\frac{y}{x} = 9.211[/tex]

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