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Use the synthetic division to find the real zeros of f(x)=2x3 +7x2+2x-3

Sagot :

Answer:

[tex]f(x) = {2x}^{3} + {7x}^{2} + 2x - 3 \\ f( \frac{1}{2} ) = 0 \\ f( - 3) = 0 \\ zeros \: = > 0 \: \: and \: \: - 3[/tex]

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