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log3 x+log3 (x+30)=log3 64

Sagot :

Answer:

x = 2

Step-by-step explanation:

[tex] log_{3}x(x+ 30) = log_{3}64 \\ x(x + 30) = 64 \\ {x}^{2} + 30x - 64 = 0 \\ x = 2 \: or \: x = - 32[/tex]

-32 is rejected because in logarithms you cannot use negative value so x=2