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Sagot :
Answer:
Length could be 14.05 ft and width 3.41 ft.
Step-by-step explanation:
The volume of the sand in the second box = 24 ft^3.
Let its base be x feet wide and y feet long.
Then 2(x + y) < 35.
The volume of sand = 0.5xy ft^3.
So 0.5xy = 24
xy = 48.
x = 48/y
Substituting ih the above inequality:
2(48/y + y) < 35
96/y + 2y < 35
2y^2 - 35y + 96 < 0
Solving 2y^2 - 35y + 96 = 0 gives y = 3.41, 14.09.
So the length could be 14.05 ft and the width 48/14 = 3.41 ft.
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