If square C is 64 in^2, then its dimensions are 8 x 8.
If square D is 81 in^2, then its dimensions are 9 x 9.
Since D is bigger than C and I sits in that extra space, then the dimensions of I are 1 x 1.
Since H is smaller than C, specifically I smaller, than its dimensions are 7 x 7.
Then, H and C make up one side of B, so 7 + 8 = 15. The dimensions of B are 15 x 15.
Since E is bigger than D by I, then the dimensions of E are 10 x 10.
If we find the length of the right side (B + C + D), which is 15 + 8 + 9 = 32, then we know that F + E + D must also add up to 32. F + 10 + 9 = 32 || F = 13. The dimensions of F are 13 x 13.
Then, F is E + G, so 13 = 10 + G. G = 3. The dimensions of G are 3 x 3.
Lastly, since we know the side length of the whole square is 32, then A + F must equal 32. 32 = A + 13. A = 19. The dimensions of A are 19 x 19.
A = 19 x 19 = 361 in^2
B = 15 x 15 = 225 in^2
C = 8 x 8 = 64 in^2
D = 9 x 9 = 81 in^2
E = 10 x 10 = 100 in^2
F = 13 x 13 = 169 in^2
G = 3 x 3 = 9 in^2
H = 7 x 7 = 49 in^2
I = 1 x 1 = 1 in^2
Hope this helps!! :)
