mountaink97
Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

At what input value will the function f(x)=x-5+2 begin to have real outputs?
[tex]f(x)= \sqrt{x-5+2} [/tex]
​

Sagot :

Answer:

3

Step-by-step explanation:

I believe the answer is 3. Based on what we know about square roots, the expression under the square root symbol must be at least zero for the output to be real.

So you have

[tex]x-5+2\geq 0[/tex]

Solving this gives you

[tex]x-3\geq 0\\x\geq 3[/tex]

Therefore, the function will begin to have real output at the input value of 3.

Hope this helped.

Answer:

5

Step-by-step explanation:

x-5+2

5-5+2=0+2=2  that's a real answer so the answer is 5 :)

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.