Answered

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What is the vertex of y=x^2-2x-1?

Sagot :

janegitari6

Answer:

(1,-2)

Step-by-step explanation:

[tex]y = {x}^{2} - 2x - 1 \\ equation \: is \: in \: the \: form \: a {x}^{2} + bx + c \\ a = 1 \\ b = - 2 \\ c = - 1 \\ solve \: for \: x \\ x = \frac{ - b}{2a} = \frac{ - ( - 2)}{2 \times 1} = \frac{2}{2} = 1 \\ subsitute \: x = 1 \:in \: the \: original\: equation \\ y = {1}^{2} - (2 \times 1) - 1 = - 2[/tex]

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