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Sheila, janice, and katen, working together at the same rate, can complete a job in 3 1/3 days. Working at the same rate, how much of the job could janice and caren do in 1 day

Sagot :

yersanabria

Answer:

Janice and Karen could do in 1 day:

  • 20% of the job.

Step-by-step explanation:

To identify how much of the job could janice and caren do in 1 day, first, we must find how much of the job make just 1 person at the same rate:

If three persons make a job in 3 1/3 days, 1 person make the job in x:

  • 3 persons ⇒ 3 1/3 days or 10/3 days
  • 1 person ⇒ x

Then:

  • [tex]x=\frac{1 person*\frac{10}{3}days }{3 persons}[/tex] (we cancel the unit "persons")
  • [tex]x=\frac{\frac{10}{3}days }{3}[/tex]
  • x = 10 days

Just a person would need 10 days to complete a job, now, we're gonna divide this value in 2 to obtain the time that need two persons to complete a job:

  • Time to complete a job between 2 persons = [tex]\frac{10}{2}days[/tex]
  • Time to complete a job between 2 persons = 5 days

How two persons need 5 days to complete a job (in this case, the two persons are Janice and Karen), we can make a simple rule of three to obtain the percentage made in 1 day:

  • 5 days ⇒ 100% of a job
  • 1 day ⇒ x

Then:

  • [tex]x=\frac{1*100}{5}[/tex] (you can use the % if you want, the result is the same)
  • [tex]x=\frac{100}{5}[/tex]
  • [tex]x=20[/tex]

As you can see, Janice and Karen just in a day could do 20% of the job.

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