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Sagot :
Answer:66.9 meters
Step-by-step explanation:
tan 18/1=x/201\
20tan18=x
201 tan 18=x
x=65.308858...
65.308858...+1.63= 66.938858...
≈ 66.9 meters tall
The height of the skyscrapers is 66.9 meters.
Given
From her eye, which stands 1.63 meters above the ground, Samantha measures the angle of elevation to the top of a prominent skyscraper to be 18°.
If she is standing at a horizontal distance of 201 meters from the base of the skyscraper,
The angle of elevation;
The angle of elevation of the sun is the angle formed between the horizontal line and your line of sight when you look at the sun.
Then,
The height of the skyscrapers is given by;
[tex]\rm Tan\theta=\dfrac{Opposite \ side}{Adjacent \ side}[/tex]
Substitute the values in the formula
[tex]\rm Tan\theta=\dfrac{Opposite \ side}{Adjacent \ side}\\\\\rm Tan18=\dfrac{x}{201}\\\\x = tan18\times 201\\\\x=65.30[/tex]
Therefore,
The height of the skyscraper is;
= 65.30 + 1.63 = 66.9
Hence, the height of the skyscrapers is 66.9 meters.
To know more about the angle of elevation click the link given below.
brainly.com/question/12992313
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