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Inside a car that was at STP, a 1.33 L bottle warms up to 130 C. If the volume of the bottle remains constant, what is the pressure, in atm, inside the hot water bottle?

Sagot :

sebassandin

Answer:

[tex]P_2=1.48atm[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to infer this problem is about the application of the Gay-Lussac's gas law to relate the initial and final pressure and temperature as shown below:

[tex]\frac{P_2}{T_2} =\frac{P_1}{T_1\\ }[/tex]

Thus, solving for the final pressure, P2, and using the temperatures in Kelvins, we obtain:

[tex]P_2 =\frac{P_1T_2}{T_1 }\\\\P_2 =\frac{1atm*403.15K}{273.15K}\\\\P_2=1.48atm[/tex]

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